Practice Rate-determining Step And The Steady-state Approximation (4.6) - Unit 6: Chemical Kinetics

Practice: Rate-Determining Step and the Steady-State Approximation

Lesson 4.6Unit 6: Chemical Kinetics

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6 sample questions

Question 1.
What is the rate-determining step (RDS)?
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Think about which step limits the reaction speed.
Question 2.
Explain how the steady-state approximation is used in kinetic studies.
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Consider why it's useful to assume intermediates don't change significantly during the reaction.
3Question 3.
What defines the rate-determining step in a multi-step reaction?
- The fastest step
- The slowest step
- The step with the most intermediates
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Think about which step limits the speed of the entire reaction.
4Question 4.
True or False: The steady-state approximation allows for changing concentrations of intermediates.
- True
- False
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What does 'constant' mean in this context?
Question 5.
Consider a reaction mechanism with three steps: A + B ⇌ C (fast), C → D (slow, RDS), and D → E (fast). Using the steady-state approximation, derive the rate law for the formation of E.
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What equilibrium constant can help connect A and B to C?
Question 6.
Explain how the introduction of a catalyst could change the rate-determining step in a reaction mechanism.
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Consider how catalysts affect energy barriers.

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