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2 cards from this section. Quick, good the night before a test.
Evaluate the left-hand limit: lim x→0⁻ (2x + 3)
Substitute values slightly less than 0.
Evaluate the right-hand limit: lim x→1⁺ (x² - 1)
Substitute values slightly greater than 1.
What is a left-hand limit?
Think about approaching the point from the lower side.
Does the limit exist where lim x→3⁻ f(x) = 1 and lim x→3⁺ f(x) = 2?
Remember, for limits to exist, both sides must agree.
Prove that lim x→2⁻ (x² + 3) = 7 and lim x→2⁺ (x² + 3) = 7. What does this imply about lim x→2?
Calculate both limits directly by substituting.
Consider the function f(x) = (x²-4)/(x-2). Determine the limits as x approaches 2 from both sides. What does this indicate about continuity?
Factor the numerator and simplify.
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