Search the courses, subjects, tracks, games and features, or jump straight to a page.
Learn it your way
A short class with Sarah and her students. The other ways are under More.
Sign up free to listen. Transcripts are free to read.
Today, we'll begin our analysis with the BJT differential amplifier. Can anyone remind me why we focus on BJTs in differential amplifiers?
Because they have good current amplification!
Exactly! BJTs are known for their high current gain, which is essential in amplification. Now, let's calculate the DC operating point. Who can help me with that?
We start by using the provided DC voltage of 2.6 V to ensure both transistors remain in the active region, right?
Correct. We want to keep Q1 and Q2 in active mode to avoid distortion. Now, if we have 2 mA flowing, how are the currents distributed?
It would be 1 mA for each transistor since they're equal!
Correct! So, we can say the collector current for both transistors is approximately 1 mA. Let's move on to the small-signal parameters.
What's the small-signal model used here?
Great question. It's important to remember that we use transconductance (gm) and output resistance (ro) for our calculations. Let's calculate gm together. Who remembers the formula?
It's gm = Ic/Vt, where Ic is the collector current and Vt is the thermal voltage, right?
Perfect! Now we can calculate the gains next.
To summarize, we've defined the operating point, established small-signal parameters, and prepped ourselves for understanding gains in the next discussion.
Now that we have our small-signal parameters, let’s compute the differential and common mode gains. What’s the formula for differential gain?
I believe it's Ad = gm * RC where RC is the load resistance?
Exactly! And why is the differential gain usually much higher than the common mode gain?
Because we designed the amplifier to maximize the differential input, filtering out common mode signals?
That's right! Now, let’s calculate the values. If gm is 0.1 mS and RC is 5.2 kΩ, what is the gain?
That would give us a differential gain of 520!
Spot on! Now what about the common-mode gain? How is that determined?
Common-mode gain is generally lower because it reacts to the average of inputs and is affected by the resistances in a different way.
Precisely! Reflecting on these calculations reinforces the concept that differential amplifiers excel at rejecting noise.
In conclusion, we calculated both the differential and common mode gains effectively and established their significance in amplifier design.
Let’s discuss output swings. Who can tell me how to determine the maximum output voltage level?
We calculate the voltage drop across the load resistors and the collector voltages!
Exactly! And why is it important for the output to have a significant swing?
So that we can accommodate larger input signals without distortion!
Correct! Let’s calculate the output swing. If our Vdc is 6.8 V and we have limits of 2.3 V and 12 V, what would that swing look like?
That would give us a positive swing of 5.2 V and a negative of 4.5 V!
Great work! Now, let’s shift to performance enhancements. Why would we replace a passive resistor with an active device?
To improve gains and stability, right?
Absolutely! This kind of enhancement emphasizes the flexibility in circuit design.
In conclusion, our exploration of output swing and performance enhancements provides insight into designing optimized circuits.
The analysis starts with calculating the DC voltage, ensuring the transistors operate in their active regions.
Calculation of transconductance and output resistance helps in understanding the amplifier's response to small input changes.
The section emphasizes the significance of these gains, demonstrating how they are derived and their implications on performance.
Critical calculations show how much the output can vary with respect to the input voltage, ensuring optimal functionality.
These analyses not only showcase the workings of differential amplifiers but also underline important design considerations in electronic circuits.
A differential amplifier with a supply voltage of 12 V and load resistances of 5.2 kΩ exhibits a differential gain of 200 and a common mode gain of approximately -2.6.
Calculating output swing shows a negative side of 4.5 V and a positive side of 5.2 V, indicating healthy headroom for signal variations.
To amplify and not distort, use the BJT's expert sort.
Imagine two friends talking. A differential amplifier hears only their conversation without the background noise around them just as the amplifier maximizes the desired signal.
DCO - Differential Current Output: Remember to focus on the current output differences in amplifying circuits.
GAD - Gain, Active Device for great gains: Active devices increase the gain in circuits.
Term
What is a Differential Amplifier?
Click to flip
Term
What does the DC Operating Point represent?
Click to flip
An amplifier that amplifies the difference between two input signals while rejecting common signals.
A type of transistor that uses both electron and hole charge carriers.
A type of transistor that controls the flow of electrons via an electric field.
The steady-state voltage and current values in a circuit necessary for an amplifier to function correctly.
Parameters that characterize the behavior of electronic devices for signals that are small deviations from an operating point.
The gain of an amplifier measured when the same input signal is applied to both terminals.
The gain of an amplifier when the difference between two input signals is used.
A measure of how effectively an input voltage controls an output current in a transistor.
The maximum peak-to-peak voltage output that an amplifier can provide.
This section covers the analysis of differential amplifiers using numerical examples, focusing on BJTs and MOSFETs, while examining small-signal parameters and output swing.
In this section, we delve deeper into differential amplifiers by analyzing numerical examples involving both BJTs and MOSFETs. Key aspects such as DC operating points, small-signal parameters, gains, input ranges, and output swings are systematically explored to reinforce understanding.
In this section, we continue our exploration of differential amplifiers by applying theoretical concepts into practical numerical examples. The focus is primarily on the following:
These analyses not only showcase the workings of differential amplifiers but also underline important design considerations in electronic circuits.